Divide Using Synthetic Division (2x^2+7x-15)÷(x+5)

$(2 x^{2} + 7 x - 15) \div (x + 5)$

Step 1

Place the numbers representing the divisor and the dividend into a division-like configuration.

$- 5$	$2$	$7$	$- 15$
	\xa0		\xa0

Step 2

The first number in the dividend $(2)$ is put into the first position of the result area (below the horizontal line).

Step 3

Multiply the newest entry in the result $(2)$ by the divisor $(- 5)$ and place the result of $(- 10)$ under the next term in the dividend $(7)$ .

Step 4

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 5

Multiply the newest entry in the result $(- 3)$ by the divisor $(- 5)$ and place the result of $(15)$ under the next term in the dividend $(- 15)$ .

Step 6

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 7

All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.

$(2) x - 3$

Step 8

Simplify the quotient polynomial.

$2 x - 3$