Divide Using Synthetic Division (2x^3+9x^2-8x-36)÷(x+2)

$(2 x^{3} + 9 x^{2} - 8 x - 36) \div (x + 2)$

Step 1

Place the numbers representing the divisor and the dividend into a division-like configuration.

$- 2$	$2$	$9$	$- 8$	$- 36$
	\xa0			\xa0

Step 2

The first number in the dividend $(2)$ is put into the first position of the result area (below the horizontal line).

Step 3

Multiply the newest entry in the result $(2)$ by the divisor $(- 2)$ and place the result of $(- 4)$ under the next term in the dividend $(9)$ .

Step 4

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 5

Multiply the newest entry in the result $(5)$ by the divisor $(- 2)$ and place the result of $(- 10)$ under the next term in the dividend $(- 8)$ .

Step 6

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 7

Multiply the newest entry in the result $(- 18)$ by the divisor $(- 2)$ and place the result of $(36)$ under the next term in the dividend $(- 36)$ .

Step 8

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 9

All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.

$2 x^{2} + 5 x - 18$