Divide Using Synthetic Division (5x^3+19x^2+6x-18)÷(x+3)

$(5 x^{3} + 19 x^{2} + 6 x - 18) \div (x + 3)$

Step 1

Place the numbers representing the divisor and the dividend into a division-like configuration.

$- 3$	$5$	$19$	$6$	$- 18$
	\xa0			\xa0

Step 2

The first number in the dividend $(5)$ is put into the first position of the result area (below the horizontal line).

Step 3

Multiply the newest entry in the result $(5)$ by the divisor $(- 3)$ and place the result of $(- 15)$ under the next term in the dividend $(19)$ .

Step 4

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 5

Multiply the newest entry in the result $(4)$ by the divisor $(- 3)$ and place the result of $(- 12)$ under the next term in the dividend $(6)$ .

Step 6

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 7

Multiply the newest entry in the result $(- 6)$ by the divisor $(- 3)$ and place the result of $(18)$ under the next term in the dividend $(- 18)$ .

Step 8

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 9

All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.

$5 x^{2} + 4 x - 6$