Divide Using Synthetic Division (6x^3+x^2-3)÷(x-7)

$(6 x^{3} + x^{2} - 3) \div (x - 7)$

Step 1

Place the numbers representing the divisor and the dividend into a division-like configuration.

$7$	$6$	$1$	$0$	$- 3$
	\xa0			\xa0

Step 2

The first number in the dividend $(6)$ is put into the first position of the result area (below the horizontal line).

Step 3

Multiply the newest entry in the result $(6)$ by the divisor $(7)$ and place the result of $(42)$ under the next term in the dividend $(1)$ .

Step 4

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 5

Multiply the newest entry in the result $(43)$ by the divisor $(7)$ and place the result of $(301)$ under the next term in the dividend $(0)$ .

Step 6

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 7

Multiply the newest entry in the result $(301)$ by the divisor $(7)$ and place the result of $(2107)$ under the next term in the dividend $(- 3)$ .

Step 8

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

Step 9

All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.

$6 x^{2} + 43 x + 301 + \frac{2104}{x - 7}$