Divide (x^2+14x+45)/(x+9)

$\frac{x^{2} + 14 x + 45}{x + 9}$

Step 1

Factor $x^{2} + 14 x + 45$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $45$ and whose sum is $14$ .

$5, 9$

Write the factored form using these integers.

$\frac{(x + 5) (x + 9)}{x + 9}$

Step 2

Cancel the common factor of $x + 9$ .

Cancel the common factor.

$\frac{(x + 5) (x + 9)}{x + 9}$

Divide $x + 5$ by $1$ .

$x + 5$

Divide (x^2+14x+45)/(x+9)

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