Divide (x^2-3x-10)/(x+2)

$\frac{x^{2} - 3 x - 10}{x + 2}$

Step 1

Factor $x^{2} - 3 x - 10$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 10$ and whose sum is $- 3$ .

$- 5, 2$

Write the factored form using these integers.

$\frac{(x - 5) (x + 2)}{x + 2}$

Step 2

Cancel the common factor of $x + 2$ .

Cancel the common factor.

$\frac{(x - 5) (x + 2)}{x + 2}$

Divide $x - 5$ by $1$ .

$x - 5$

Divide (x^2-3x-10)/(x+2)

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