Divide (x^2-x-12)/(x-4)

$\frac{x^{2} - x - 12}{x - 4}$

Step 1

Factor $x^{2} - x - 12$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 12$ and whose sum is $- 1$ .

$- 4, 3$

Write the factored form using these integers.

$\frac{(x - 4) (x + 3)}{x - 4}$

Step 2

Cancel the common factor of $x - 4$ .

Cancel the common factor.

$\frac{(x - 4) (x + 3)}{x - 4}$

Divide $x + 3$ by $1$ .

$x + 3$

Divide (x^2-x-12)/(x-4)

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