Divide (x^2-x-6)÷(x-3)

$(x^{2} - x - 6) \div (x - 3)$

Step 1

Rewrite the division as a fraction.

$\frac{x^{2} - x - 6}{x - 3}$

Step 2

Factor $x^{2} - x - 6$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 6$ and whose sum is $- 1$ .

$- 3, 2$

Write the factored form using these integers.

$\frac{(x - 3) (x + 2)}{x - 3}$

Step 3

Cancel the common factor of $x - 3$ .

Cancel the common factor.

$\frac{(x - 3) (x + 2)}{x - 3}$

Divide $x + 2$ by $1$ .

$x + 2$

Divide (x^2-x-6)÷(x-3)

Related Questions

Support LCMGCF.com by disabling your adblocker.