Divide (x^3-1)/(x-1)

$\frac{x^{3} - 1}{x - 1}$

Step 1

Simplify the numerator.

Rewrite $1$ as $1^{3}$ .

$\frac{x^{3} - 1^{3}}{x - 1}$

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = x$ and $b = 1$ .

$\frac{(x - 1) (x^{2} + x \cdot 1 + 1^{2})}{x - 1}$

Simplify.

Multiply $x$ by $1$ .

$\frac{(x - 1) (x^{2} + x + 1^{2})}{x - 1}$

One to any power is one.

$\frac{(x - 1) (x^{2} + x + 1)}{x - 1}$

Step 2

Cancel the common factor of $x - 1$ .

Cancel the common factor.

$\frac{(x - 1) (x^{2} + x + 1)}{x - 1}$

Divide $x^{2} + x + 1$ by $1$ .

$x^{2} + x + 1$

Divide (x^3-1)/(x-1)

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