Divide (x^3-15x^2+68x-96)/(x-3)

$\frac{x^{3} - 15 x^{2} + 68 x - 96}{x - 3}$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$3$

$x^{3}$

$15 x^{2}$

$68 x$

$96$

Step 2

Divide the highest order term in the dividend $x^{3}$ by the highest order term in divisor $x$ .

					$x^{2}$
	$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$

Step 3

Multiply the new quotient term by the divisor.

				$x^{2}$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			+	$x^{3}$	-	$3 x^{2}$

Step 4

The expression needs to be subtracted from the dividend, so change all the signs in $x^{3} - 3 x^{2}$

				$x^{2}$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$

Step 5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$

Step 6

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$

Step 7

Divide the highest order term in the dividend $- 12 x^{2}$ by the highest order term in divisor $x$ .

				$x^{2}$	-	$12 x$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$

Step 8

Multiply the new quotient term by the divisor.

				$x^{2}$	-	$12 x$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$
					-	$12 x^{2}$	+	$36 x$

Step 9

The expression needs to be subtracted from the dividend, so change all the signs in $- 12 x^{2} + 36 x$

				$x^{2}$	-	$12 x$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$
					+	$12 x^{2}$	-	$36 x$

Step 10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	-	$12 x$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$
					+	$12 x^{2}$	-	$36 x$
							+	$32 x$

Step 11

Pull the next terms from the original dividend down into the current dividend.

				$x^{2}$	-	$12 x$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$
					+	$12 x^{2}$	-	$36 x$
							+	$32 x$	-	$96$

Step 12

Divide the highest order term in the dividend $32 x$ by the highest order term in divisor $x$ .

				$x^{2}$	-	$12 x$	+	$32$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$
					+	$12 x^{2}$	-	$36 x$
							+	$32 x$	-	$96$

Step 13

Multiply the new quotient term by the divisor.

				$x^{2}$	-	$12 x$	+	$32$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$
					+	$12 x^{2}$	-	$36 x$
							+	$32 x$	-	$96$
							+	$32 x$	-	$96$

Step 14

The expression needs to be subtracted from the dividend, so change all the signs in $32 x - 96$

				$x^{2}$	-	$12 x$	+	$32$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$
					+	$12 x^{2}$	-	$36 x$
							+	$32 x$	-	$96$
							-	$32 x$	+	$96$

Step 15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$x^{2}$	-	$12 x$	+	$32$
$x$	-	$3$		$x^{3}$	-	$15 x^{2}$	+	$68 x$	-	$96$
			-	$x^{3}$	+	$3 x^{2}$
					-	$12 x^{2}$	+	$68 x$
					+	$12 x^{2}$	-	$36 x$
							+	$32 x$	-	$96$
							-	$32 x$	+	$96$
										$0$

Step 16

Since the remander is $0$ , the final answer is the quotient.

$x^{2} - 12 x + 32$

Divide (x^3-15x^2+68x-96)/(x-3)

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