Divide (x^3-512)/(x-8)

$\frac{x^{3} - 512}{x - 8}$

Step 1

Simplify the numerator.

Rewrite $512$ as $8^{3}$ .

$\frac{x^{3} - 8^{3}}{x - 8}$

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = x$ and $b = 8$ .

$\frac{(x - 8) (x^{2} + x \cdot 8 + 8^{2})}{x - 8}$

Simplify.

Move $8$ to the left of $x$ .

$\frac{(x - 8) (x^{2} + 8 \cdot x + 8^{2})}{x - 8}$

Raise $8$ to the power of $2$ .

$\frac{(x - 8) (x^{2} + 8 x + 64)}{x - 8}$

Step 2

Cancel the common factor of $x - 8$ .

Cancel the common factor.

$\frac{(x - 8) (x^{2} + 8 x + 64)}{x - 8}$

Divide $x^{2} + 8 x + 64$ by $1$ .

$x^{2} + 8 x + 64$

Divide (x^3-512)/(x-8)

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