Divide ((x^3-8)/(x^2+3x-10))÷((8x-40)/(x^2-25))

$\frac{x^{3} - 8}{x^{2} + 3 x - 10} \div \frac{8 x - 40}{x^{2} - 25}$

To divide by a fraction, multiply by its reciprocal.

$\frac{x^{3} - 8}{x^{2} + 3 x - 10} \cdot \frac{x^{2} - 25}{8 x - 40}$

Simplify the numerator.

Rewrite $8$ as $2^{3}$ .

$\frac{x^{3} - 2^{3}}{x^{2} + 3 x - 10} \cdot \frac{x^{2} - 25}{8 x - 40}$

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = x$ and $b = 2$ .

$\frac{(x - 2) (x^{2} + x \cdot 2 + 2^{2})}{x^{2} + 3 x - 10} \cdot \frac{x^{2} - 25}{8 x - 40}$

Simplify.

Move $2$ to the left of $x$ .

$\frac{(x - 2) (x^{2} + 2 \cdot x + 2^{2})}{x^{2} + 3 x - 10} \cdot \frac{x^{2} - 25}{8 x - 40}$

Raise $2$ to the power of $2$ .

$\frac{(x - 2) (x^{2} + 2 x + 4)}{x^{2} + 3 x - 10} \cdot \frac{x^{2} - 25}{8 x - 40}$

Factor $x^{2} + 3 x - 10$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 10$ and whose sum is $3$ .

$- 2, 5$

Write the factored form using these integers.

$\frac{(x - 2) (x^{2} + 2 x + 4)}{(x - 2) (x + 5)} \cdot \frac{x^{2} - 25}{8 x - 40}$

Cancel the common factor of $x - 2$ .

Cancel the common factor.

$\frac{(x - 2) (x^{2} + 2 x + 4)}{(x - 2) (x + 5)} \cdot \frac{x^{2} - 25}{8 x - 40}$

Rewrite the expression.

$\frac{x^{2} + 2 x + 4}{x + 5} \cdot \frac{x^{2} - 25}{8 x - 40}$

Simplify the numerator.

Rewrite $25$ as $5^{2}$ .

$\frac{x^{2} + 2 x + 4}{x + 5} \cdot \frac{x^{2} - 5^{2}}{8 x - 40}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 5$ .

$\frac{x^{2} + 2 x + 4}{x + 5} \cdot \frac{(x + 5) (x - 5)}{8 x - 40}$

Factor $8$ out of $8 x - 40$ .

Factor $8$ out of $8 x$ .

$\frac{x^{2} + 2 x + 4}{x + 5} \cdot \frac{(x + 5) (x - 5)}{8 (x) - 40}$

Factor $8$ out of $- 40$ .

$\frac{x^{2} + 2 x + 4}{x + 5} \cdot \frac{(x + 5) (x - 5)}{8 x + 8 \cdot - 5}$

Factor $8$ out of $8 x + 8 \cdot - 5$ .

$\frac{x^{2} + 2 x + 4}{x + 5} \cdot \frac{(x + 5) (x - 5)}{8 (x - 5)}$

Cancel the common factor of $x + 5$ .

Cancel the common factor.

$\frac{x^{2} + 2 x + 4}{x + 5} \cdot \frac{(x + 5) (x - 5)}{8 (x - 5)}$

Rewrite the expression.

$(x^{2} + 2 x + 4) \frac{x - 5}{8 (x - 5)}$

Cancel the common factor of $x - 5$ .

Cancel the common factor.

$(x^{2} + 2 x + 4) \frac{x - 5}{8 (x - 5)}$

Rewrite the expression.

$(x^{2} + 2 x + 4) \frac{1}{8}$

Apply the distributive property.

$x^{2} \frac{1}{8} + 2 x \frac{1}{8} + 4 (\frac{1}{8})$

Simplify.

Combine $x^{2}$ and $\frac{1}{8}$ .

$\frac{x^{2}}{8} + 2 x \frac{1}{8} + 4 (\frac{1}{8})$

Cancel the common factor of $2$ .

Factor $2$ out of $2 x$ .

$\frac{x^{2}}{8} + 2 (x) \frac{1}{8} + 4 (\frac{1}{8})$

Factor $2$ out of $8$ .

$\frac{x^{2}}{8} + 2 (x) \frac{1}{2 (4)} + 4 (\frac{1}{8})$

Cancel the common factor.

$\frac{x^{2}}{8} + 2 x \frac{1}{2 \cdot 4} + 4 (\frac{1}{8})$

Rewrite the expression.

$\frac{x^{2}}{8} + x \frac{1}{4} + 4 (\frac{1}{8})$

Combine $x$ and $\frac{1}{4}$ .

$\frac{x^{2}}{8} + \frac{x}{4} + 4 (\frac{1}{8})$

Cancel the common factor of $4$ .

Factor $4$ out of $8$ .

$\frac{x^{2}}{8} + \frac{x}{4} + 4 \frac{1}{4 (2)}$

Cancel the common factor.

$\frac{x^{2}}{8} + \frac{x}{4} + 4 \frac{1}{4 \cdot 2}$

Rewrite the expression.

$\frac{x^{2}}{8} + \frac{x}{4} + \frac{1}{2}$

Divide ((x^3-8)/(x^2+3x-10))÷((8x-40)/(x^2-25))

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