Divide (x^3-8)/(x^2-4)

$\frac{x^{3} - 8}{x^{2} - 4}$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x^{2}$

$0 x$

$4$

$x^{3}$

$0 x^{2}$

$0 x$

$8$

Step 2

Divide the highest order term in the dividend $x^{3}$ by the highest order term in divisor $x^{2}$ .

$x$

$x^{2}$

$0 x$

$4$

$x^{3}$

$0 x^{2}$

$0 x$

$8$

Step 3

Multiply the new quotient term by the divisor.

$x$

$x^{2}$

$0 x$

$4$

$x^{3}$

$0 x^{2}$

$0 x$

$8$

$x^{3}$

$0$

$4 x$

Step 4

The expression needs to be subtracted from the dividend, so change all the signs in $x^{3} + 0 - 4 x$

$x$

$x^{2}$

$0 x$

$4$

$x^{3}$

$0 x^{2}$

$0 x$

$8$

$x^{3}$

$0$

$4 x$

Step 5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$x$

$x^{2}$

$0 x$

$4$

$x^{3}$

$0 x^{2}$

$0 x$

$8$

$x^{3}$

$0$

$4 x$

Step 6

Pull the next term from the original dividend down into the current dividend.

$x$

$x^{2}$

$0 x$

$4$

$x^{3}$

$0 x^{2}$

$0 x$

$8$

$x^{3}$

$0$

$4 x$

$8$

Step 7

The final answer is the quotient plus the remainder over the divisor.

$x + \frac{4 x - 8}{x^{2} - 4}$

Divide (x^3-8)/(x^2-4)

Related Questions

Support LCMGCF.com by disabling your adblocker.