Evaluate 1/(0^2-9)

$\frac{1}{0^{2} - 9}$

Simplify the denominator.

Raising $0$ to any positive power yields $0$ .

$\frac{1}{0 - 9}$

Subtract $9$ from $0$ .

$\frac{1}{- 9}$

$\frac{1}{- 9}$

Move the negative in front of the fraction.

$- \frac{1}{9}$

The result can be shown in multiple forms.

Exact Form:

$- \frac{1}{9}$

Decimal Form:

$- 0.\overline{1}$

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