Evaluate 1+2-(3(4))÷2

$1 + 2 - 3 (4) \div 2$

Find the common denominator.

Write $1$ as a fraction with denominator $1$ .

$\frac{1}{1} + 2 - 3 (4) \div 2$

Multiply $\frac{1}{1}$ by $\frac{2}{2}$ .

$\frac{1}{1} \cdot \frac{2}{2} + 2 - 3 (4) \div 2$

Multiply $\frac{1}{1}$ by $\frac{2}{2}$ .

$\frac{2}{2} + 2 - 3 (4) \div 2$

Write $2$ as a fraction with denominator $1$ .

$\frac{2}{2} + \frac{2}{1} - 3 (4) \div 2$

Multiply $\frac{2}{1}$ by $\frac{2}{2}$ .

$\frac{2}{2} + \frac{2}{1} \cdot \frac{2}{2} - 3 (4) \div 2$

Multiply $\frac{2}{1}$ by $\frac{2}{2}$ .

$\frac{2}{2} + \frac{2 \cdot 2}{2} - 3 (4) \div 2$

Combine the numerators over the common denominator.

$\frac{2 + 2 \cdot 2 - 3 \cdot 4}{2}$

Simplify each term.

Multiply $2$ by $2$ .

$\frac{2 + 4 - 3 \cdot 4}{2}$

Multiply $- 3$ by $4$ .

$\frac{2 + 4 - 12}{2}$

Simplify the expression.

Add $2$ and $4$ .

$\frac{6 - 12}{2}$

Subtract $12$ from $6$ .

$\frac{- 6}{2}$

Divide $- 6$ by $2$ .

$- 3$