Evaluate (1+3*5)/(18-4^2)-|-11|

$\frac{1 + 3 \cdot 5}{18 - 4^{2}} - | - 11 |$

Step 1

Simplify the expression.

Multiply $3$ by $5$ .

$\frac{1 + 15}{18 - 4^{2}} - | - 11 |$

Add $1$ and $15$ .

$\frac{16}{18 - 4^{2}} - | - 11 |$

Step 2

Simplify each term.

Simplify the denominator.

Raise $4$ to the power of $2$ .

$\frac{16}{18 - 1 \cdot 16} - | - 11 |$

Multiply $- 1$ by $16$ .

$\frac{16}{18 - 16} - | - 11 |$

Subtract $16$ from $18$ .

$\frac{16}{2} - | - 11 |$

Divide $16$ by $2$ .

$8 - | - 11 |$

The absolute value is the distance between a number and zero. The distance between $- 11$ and $0$ is $11$ .

$8 - 1 \cdot 11$

Multiply $- 1$ by $11$ .

$8 - 11$

Step 3

Subtract $11$ from $8$ .

$- 3$