Evaluate 1/(3+i)

$\frac{1}{3 + i}$

Step 1

Multiply the numerator and denominator of $\frac{1}{3 + 1 i}$ by the conjugate of $3 + 1 i$ to make the denominator real.

$\frac{1}{3 + 1 i} \cdot \frac{3 - i}{3 - i}$

Step 2

Multiply.

Combine.

$\frac{1 (3 - i)}{(3 + 1 i) (3 - i)}$

Multiply $3 - i$ by $1$ .

$\frac{3 - i}{(3 + 1 i) (3 - i)}$

Simplify the denominator.

Expand $(3 + 1 i) (3 - i)$ using the FOIL Method.

Apply the distributive property.

$\frac{3 - i}{3 (3 - i) + 1 i (3 - i)}$

Apply the distributive property.

$\frac{3 - i}{3 \cdot 3 + 3 (- i) + 1 i (3 - i)}$

Apply the distributive property.

$\frac{3 - i}{3 \cdot 3 + 3 (- i) + 1 i \cdot 3 + 1 i (- i)}$

Simplify.

Multiply $3$ by $3$ .

$\frac{3 - i}{9 + 3 (- i) + 1 i \cdot 3 + 1 i (- i)}$

Multiply $- 1$ by $3$ .

$\frac{3 - i}{9 - 3 i + 1 i \cdot 3 + 1 i (- i)}$

Multiply $3$ by $1$ .

$\frac{3 - i}{9 - 3 i + 3 i + 1 i (- i)}$

Multiply $- 1$ by $1$ .

$\frac{3 - i}{9 - 3 i + 3 i - i i}$

Raise $i$ to the power of $1$ .

$\frac{3 - i}{9 - 3 i + 3 i - (i^{1} i)}$

Raise $i$ to the power of $1$ .

$\frac{3 - i}{9 - 3 i + 3 i - (i^{1} i^{1})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{3 - i}{9 - 3 i + 3 i - i^{1 + 1}}$

Add $1$ and $1$ .

$\frac{3 - i}{9 - 3 i + 3 i - i^{2}}$

Add $- 3 i$ and $3 i$ .

$\frac{3 - i}{9 + 0 - i^{2}}$

Add $9$ and $0$ .

$\frac{3 - i}{9 - i^{2}}$

Simplify each term.

Rewrite $i^{2}$ as $- 1$ .

$\frac{3 - i}{9 - - 1}$

Multiply $- 1$ by $- 1$ .

$\frac{3 - i}{9 + 1}$

Add $9$ and $1$ .

$\frac{3 - i}{10}$

Step 3

Split the fraction $\frac{3 - i}{10}$ into two fractions.

$\frac{3}{10} + \frac{- i}{10}$

Step 4

Move the negative in front of the fraction.

$\frac{3}{10} - \frac{i}{10}$

Evaluate 1/(3+i)

Related Questions

Support LCMGCF.com by disabling your adblocker.