Evaluate 1/5(6+3+1)^2

$\frac{1}{5} {(6 + 3 + 1)}^{2}$

Simplify the expression.

Add $6$ and $3$ .

$\frac{1}{5} \cdot {(9 + 1)}^{2}$

Add $9$ and $1$ .

$\frac{1}{5} \cdot 10^{2}$

Raise $10$ to the power of $2$ .

$\frac{1}{5} \cdot 100$

$\frac{1}{5} \cdot 100$

Cancel the common factor of $5$ .

Factor $5$ out of $100$ .

$\frac{1}{5} \cdot (5 (20))$

Cancel the common factor.

$\frac{1}{5} \cdot (5 \cdot 20)$

Rewrite the expression.

$20$

$20$

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