Evaluate 1+6÷3-(9-5)

$1 + 6 \div 3 - (9 - 5)$

Step 1

Find the common denominator.

Write $1$ as a fraction with denominator $1$ .

$\frac{1}{1} + 6 \div 3 - (9 - 5)$

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$\frac{1}{1} \cdot \frac{3}{3} + 6 \div 3 - (9 - 5)$

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$\frac{3}{3} + 6 \div 3 - (9 - 5)$

Write $- (9 - 5)$ as a fraction with denominator $1$ .

$\frac{3}{3} + 6 \div 3 + \frac{- (9 - 5)}{1}$

Multiply $\frac{- (9 - 5)}{1}$ by $\frac{3}{3}$ .

$\frac{3}{3} + 6 \div 3 + \frac{- (9 - 5)}{1} \cdot \frac{3}{3}$

Multiply $\frac{- (9 - 5)}{1}$ by $\frac{3}{3}$ .

$\frac{3}{3} + 6 \div 3 + \frac{- (9 - 5) \cdot 3}{3}$

Step 2

Combine the numerators over the common denominator.

$\frac{3 + 6 - (9 - 5) \cdot 3}{3}$

Step 3

Simplify each term.

Subtract $5$ from $9$ .

$\frac{3 + 6 - 1 \cdot 4 \cdot 3}{3}$

Multiply $- 1 \cdot 4 \cdot 3$ .

Multiply $- 1$ by $4$ .

$\frac{3 + 6 - 4 \cdot 3}{3}$

Multiply $- 4$ by $3$ .

$\frac{3 + 6 - 12}{3}$

Step 4

Simplify the expression.

Add $3$ and $6$ .

$\frac{9 - 12}{3}$

Subtract $12$ from $9$ .

$\frac{- 3}{3}$

Divide $- 3$ by $3$ .

$- 1$