Evaluate (1+i)^5

${(1 + i)}^{5}$

Step 1

Use the Binomial Theorem.

$1^{5} + 5 \cdot 1^{4} i + 10 \cdot 1^{3} i^{2} + 10 \cdot 1^{2} i^{3} + 5 \cdot 1 i^{4} + i^{5}$

Step 2

Simplify terms.

Simplify each term.

One to any power is one.

$1 + 5 \cdot 1^{4} i + 10 \cdot 1^{3} i^{2} + 10 \cdot 1^{2} i^{3} + 5 \cdot 1 i^{4} + i^{5}$

One to any power is one.

$1 + 5 \cdot 1 i + 10 \cdot 1^{3} i^{2} + 10 \cdot 1^{2} i^{3} + 5 \cdot 1 i^{4} + i^{5}$

Multiply $5$ by $1$ .

$1 + 5 i + 10 \cdot 1^{3} i^{2} + 10 \cdot 1^{2} i^{3} + 5 \cdot 1 i^{4} + i^{5}$

One to any power is one.

$1 + 5 i + 10 \cdot 1 i^{2} + 10 \cdot 1^{2} i^{3} + 5 \cdot 1 i^{4} + i^{5}$

Multiply $10$ by $1$ .

$1 + 5 i + 10 i^{2} + 10 \cdot 1^{2} i^{3} + 5 \cdot 1 i^{4} + i^{5}$

Rewrite $i^{2}$ as $- 1$ .

$1 + 5 i + 10 \cdot - 1 + 10 \cdot 1^{2} i^{3} + 5 \cdot 1 i^{4} + i^{5}$

Multiply $10$ by $- 1$ .

$1 + 5 i - 10 + 10 \cdot 1^{2} i^{3} + 5 \cdot 1 i^{4} + i^{5}$

One to any power is one.

$1 + 5 i - 10 + 10 \cdot 1 i^{3} + 5 \cdot 1 i^{4} + i^{5}$

Multiply $10$ by $1$ .

$1 + 5 i - 10 + 10 i^{3} + 5 \cdot 1 i^{4} + i^{5}$

Factor out $i^{2}$ .

$1 + 5 i - 10 + 10 (i^{2} \cdot i) + 5 \cdot 1 i^{4} + i^{5}$

Rewrite $i^{2}$ as $- 1$ .

$1 + 5 i - 10 + 10 (- 1 \cdot i) + 5 \cdot 1 i^{4} + i^{5}$

Rewrite $- 1 i$ as $- i$ .

$1 + 5 i - 10 + 10 (- i) + 5 \cdot 1 i^{4} + i^{5}$

Multiply $- 1$ by $10$ .

$1 + 5 i - 10 - 10 i + 5 \cdot 1 i^{4} + i^{5}$

Multiply $5$ by $1$ .

$1 + 5 i - 10 - 10 i + 5 i^{4} + i^{5}$

Rewrite $i^{4}$ as $1$ .

Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

$1 + 5 i - 10 - 10 i + 5 {(i^{2})}^{2} + i^{5}$

Rewrite $i^{2}$ as $- 1$ .

$1 + 5 i - 10 - 10 i + 5 {(- 1)}^{2} + i^{5}$

Raise $- 1$ to the power of $2$ .

$1 + 5 i - 10 - 10 i + 5 \cdot 1 + i^{5}$

Multiply $5$ by $1$ .

$1 + 5 i - 10 - 10 i + 5 + i^{5}$

Factor out $i^{4}$ .

$1 + 5 i - 10 - 10 i + 5 + i^{4} i$

Rewrite $i^{4}$ as $1$ .

Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

$1 + 5 i - 10 - 10 i + 5 + {(i^{2})}^{2} i$

Rewrite $i^{2}$ as $- 1$ .

$1 + 5 i - 10 - 10 i + 5 + {(- 1)}^{2} i$

Raise $- 1$ to the power of $2$ .

$1 + 5 i - 10 - 10 i + 5 + 1 i$

Multiply $i$ by $1$ .

$1 + 5 i - 10 - 10 i + 5 + i$

Simplify by adding terms.

Subtract $10$ from $1$ .

$- 9 + 5 i - 10 i + 5 + i$

Add $- 9$ and $5$ .

$- 4 + 5 i - 10 i + i$

Subtract $10 i$ from $5 i$ .

$- 4 - 5 i + i$

Add $- 5 i$ and $i$ .

$- 4 - 4 i$

Evaluate (1+i)^5

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