Evaluate -1/(( square root of 16)^3)

$\frac{- 1}{{(\sqrt{16})}^{3}}$

Simplify the denominator.

Rewrite $16$ as $4^{2}$ .

$\frac{- 1}{{\sqrt{4^{2}}}^{3}}$

Pull terms out from under the radical, assuming positive real numbers.

$\frac{- 1}{4^{3}}$

Raise $4$ to the power of $3$ .

$\frac{- 1}{64}$

Move the negative in front of the fraction.

$- \frac{1}{64}$

The result can be shown in multiple forms.

Exact Form:

$- \frac{1}{64}$

Decimal Form:

$- 0.015625$