Evaluate (10-(2-8)^2)÷(3^2+2^2)

$(10 - {(2 - 8)}^{2}) \div (3^{2} + 2^{2})$

Step 1

Rewrite the division as a fraction.

$\frac{10 - {(2 - 8)}^{2}}{3^{2} + 2^{2}}$

Step 2

Simplify the numerator.

Subtract $8$ from $2$ .

$\frac{10 - {(- 6)}^{2}}{3^{2} + 2^{2}}$

Raise $- 6$ to the power of $2$ .

$\frac{10 - 1 \cdot 36}{3^{2} + 2^{2}}$

Multiply $- 1$ by $36$ .

$\frac{10 - 36}{3^{2} + 2^{2}}$

Subtract $36$ from $10$ .

$\frac{- 26}{3^{2} + 2^{2}}$

$\frac{- 26}{3^{2} + 2^{2}}$

Step 3

Simplify the denominator.

Raise $3$ to the power of $2$ .

$\frac{- 26}{9 + 2^{2}}$

Raise $2$ to the power of $2$ .

$\frac{- 26}{9 + 4}$

Add $9$ and $4$ .

$\frac{- 26}{13}$

$\frac{- 26}{13}$

Step 4

Divide $- 26$ by $13$ .

$- 2$

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