Evaluate 10^(4x+1)>=100^(x-2)

$10^{4 x + 1} \geq 100^{x - 2}$

Create equivalent expressions in the equation that all have equal bases.

$10^{4 x + 1} \geq 10^{2 (x - 2)}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$4 x + 1 \geq 2 (x - 2)$

Solve for $x$ .

Simplify $2 (x - 2)$ .

Rewrite.

$4 x + 1 \geq 0 + 0 + 2 (x - 2)$

Simplify by adding zeros.

$4 x + 1 \geq 2 (x - 2)$

Apply the distributive property.

$4 x + 1 \geq 2 x + 2 \cdot - 2$

Multiply $2$ by $- 2$ .

$4 x + 1 \geq 2 x - 4$

Move all terms containing $x$ to the left side of the inequality.

Subtract $2 x$ from both sides of the inequality.

$4 x + 1 - 2 x \geq - 4$

Subtract $2 x$ from $4 x$ .

$2 x + 1 \geq - 4$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$2 x \geq - 4 - 1$

Subtract $1$ from $- 4$ .

$2 x \geq - 5$

Divide each term in $2 x \geq - 5$ by $2$ and simplify.

Divide each term in $2 x \geq - 5$ by $2$ .

$\frac{2 x}{2} \geq \frac{- 5}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} \geq \frac{- 5}{2}$

Divide $x$ by $1$ .

$x \geq \frac{- 5}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x \geq - \frac{5}{2}$

Use each root to create test intervals.

$x < - \frac{5}{2}$

$x > - \frac{5}{2}$

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

Test a value on the interval $x < - \frac{5}{2}$ to see if it makes the inequality true.

Choose a value on the interval $x < - \frac{5}{2}$ and see if this value makes the original inequality true.

$x = - 5$

Replace $x$ with $- 5$ in the original inequality.

$10^{4 (- 5) + 1} \geq 100^{(- 5) - 2}$

The left side $1 E - 19$ is equal to the right side $1 E - 14$ , which means that the given statement is always true.

True

Test a value on the interval $x > - \frac{5}{2}$ to see if it makes the inequality true.

Choose a value on the interval $x > - \frac{5}{2}$ and see if this value makes the original inequality true.

$x = 0$

Replace $x$ with $0$ in the original inequality.

$10^{4 (0) + 1} \geq 100^{(0) - 2}$

The left side $10$ is greater than the right side $0.0001$ , which means that the given statement is always true.

True

Compare the intervals to determine which ones satisfy the original inequality.

$x < - \frac{5}{2}$ True

$x > - \frac{5}{2}$ True

$x < - \frac{5}{2}$ True

$x > - \frac{5}{2}$ True

The solution consists of all of the true intervals.

$x \leq - \frac{5}{2}$ or $x \geq - \frac{5}{2}$

Combine the intervals.

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$

Evaluate 10^(4x+1)>=100^(x-2)

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