Evaluate (12(30-(9+4^2)))/(|10|-|-6|)

$\frac{12 (30 - (9 + 4^{2}))}{| 10 | - | - 6 |}$

Step 1

Simplify the numerator.

Raise $4$ to the power of $2$ .

$\frac{12 (30 - (9 + 16))}{| 10 | - | - 6 |}$

Add $9$ and $16$ .

$\frac{12 (30 - 1 \cdot 25)}{| 10 | - | - 6 |}$

Multiply $- 1$ by $25$ .

$\frac{12 (30 - 25)}{| 10 | - | - 6 |}$

Subtract $25$ from $30$ .

$\frac{12 \cdot 5}{| 10 | - | - 6 |}$

Step 2

Simplify the denominator.

The absolute value is the distance between a number and zero. The distance between $0$ and $10$ is $10$ .

$\frac{12 \cdot 5}{10 - | - 6 |}$

The absolute value is the distance between a number and zero. The distance between $- 6$ and $0$ is $6$ .

$\frac{12 \cdot 5}{10 - 1 \cdot 6}$

Multiply $- 1$ by $6$ .

$\frac{12 \cdot 5}{10 - 6}$

Subtract $6$ from $10$ .

$\frac{12 \cdot 5}{4}$

Step 3

Simplify the expression.

Multiply $12$ by $5$ .

$\frac{60}{4}$

Divide $60$ by $4$ .

$15$