Evaluate |15-9(2/3)|

$| 15 - 9 (\frac{2}{3}) |$

Simplify each term.

Cancel the common factor of $3$ .

Factor $3$ out of $- 9$ .

$| 15 + 3 (- 3) \frac{2}{3} |$

Cancel the common factor.

$| 15 + 3 \cdot - 3 \frac{2}{3} |$

Rewrite the expression.

$| 15 - 3 \cdot 2 |$

Multiply $- 3$ by $2$ .

$| 15 - 6 |$

Subtract $6$ from $15$ .

$| 9 |$

The absolute value is the distance between a number and zero. The distance between $0$ and $9$ is $9$ .

$9$