Evaluate (18-(-1-7)^2)+16÷(2^4)

$(18 - {(- 1 - 7)}^{2}) + 16 \div 2^{4}$

Find the common denominator.

Raise $2$ to the power of $4$ .

$18 - {(- 1 - 7)}^{2} + 16 \div 16$

Write $18$ as a fraction with denominator $1$ .

$\frac{18}{1} - {(- 1 - 7)}^{2} + 16 \div 16$

Multiply $\frac{18}{1}$ by $\frac{16}{16}$ .

$\frac{18}{1} \cdot \frac{16}{16} - {(- 1 - 7)}^{2} + 16 \div 16$

Multiply $\frac{18}{1}$ by $\frac{16}{16}$ .

$\frac{18 \cdot 16}{16} - {(- 1 - 7)}^{2} + 16 \div 16$

Write $- {(- 1 - 7)}^{2}$ as a fraction with denominator $1$ .

$\frac{18 \cdot 16}{16} + \frac{- {(- 1 - 7)}^{2}}{1} + 16 \div 16$

Multiply $\frac{- {(- 1 - 7)}^{2}}{1}$ by $\frac{16}{16}$ .

$\frac{18 \cdot 16}{16} + \frac{- {(- 1 - 7)}^{2}}{1} \cdot \frac{16}{16} + 16 \div 16$

Multiply $\frac{- {(- 1 - 7)}^{2}}{1}$ by $\frac{16}{16}$ .

$\frac{18 \cdot 16}{16} + \frac{- {(- 1 - 7)}^{2} \cdot 16}{16} + 16 \div 16$

Combine the numerators over the common denominator.

$\frac{18 \cdot 16 - {(- 1 - 7)}^{2} \cdot 16 + 16}{16}$

Simplify each term.

Multiply $18$ by $16$ .

$\frac{288 - {(- 1 - 7)}^{2} \cdot 16 + 16}{16}$

Subtract $7$ from $- 1$ .

$\frac{288 - {(- 8)}^{2} \cdot 16 + 16}{16}$

Raise $- 8$ to the power of $2$ .

$\frac{288 - 1 \cdot 64 \cdot 16 + 16}{16}$

Multiply $- 1$ by $64$ .

$\frac{288 - 64 \cdot 16 + 16}{16}$

Multiply $- 64$ by $16$ .

$\frac{288 - 1024 + 16}{16}$

Simplify the expression.

Subtract $1024$ from $288$ .

$\frac{- 736 + 16}{16}$

Add $- 736$ and $16$ .

$\frac{- 720}{16}$

Divide $- 720$ by $16$ .

$- 45$