Evaluate 18-12+2*3^2-12÷(1+1)

$18 - 12 + 2 \cdot 3^{2} - 12 \div (1 + 1)$

Find the common denominator.

Write $18$ as a fraction with denominator $1$ .

$\frac{18}{1} - 12 + 2 \cdot 3^{2} - 12 \div (1 + 1)$

Multiply $\frac{18}{1}$ by $\frac{1 + 1}{1 + 1}$ .

$\frac{18}{1} \cdot \frac{1 + 1}{1 + 1} - 12 + 2 \cdot 3^{2} - 12 \div (1 + 1)$

Multiply $\frac{18}{1}$ by $\frac{1 + 1}{1 + 1}$ .

$\frac{18 (1 + 1)}{1 + 1} - 12 + 2 \cdot 3^{2} - 12 \div (1 + 1)$

Write $- 12$ as a fraction with denominator $1$ .

$\frac{18 (1 + 1)}{1 + 1} + \frac{- 12}{1} + 2 \cdot 3^{2} - 12 \div (1 + 1)$

Multiply $\frac{- 12}{1}$ by $\frac{1 + 1}{1 + 1}$ .

$\frac{18 (1 + 1)}{1 + 1} + \frac{- 12}{1} \cdot \frac{1 + 1}{1 + 1} + 2 \cdot 3^{2} - 12 \div (1 + 1)$

Multiply $\frac{- 12}{1}$ by $\frac{1 + 1}{1 + 1}$ .

$\frac{18 (1 + 1)}{1 + 1} + \frac{- 12 (1 + 1)}{1 + 1} + 2 \cdot 3^{2} - 12 \div (1 + 1)$

Write $2 \cdot 3^{2}$ as a fraction with denominator $1$ .

$\frac{18 (1 + 1)}{1 + 1} + \frac{- 12 (1 + 1)}{1 + 1} + \frac{2 \cdot 3^{2}}{1} - 12 \div (1 + 1)$

Multiply $\frac{2 \cdot 3^{2}}{1}$ by $\frac{1 + 1}{1 + 1}$ .

$\frac{18 (1 + 1)}{1 + 1} + \frac{- 12 (1 + 1)}{1 + 1} + \frac{2 \cdot 3^{2}}{1} \cdot \frac{1 + 1}{1 + 1} - 12 \div (1 + 1)$

Multiply $\frac{2 \cdot 3^{2}}{1}$ by $\frac{1 + 1}{1 + 1}$ .

$\frac{18 (1 + 1)}{1 + 1} + \frac{- 12 (1 + 1)}{1 + 1} + \frac{2 \cdot 3^{2} (1 + 1)}{1 + 1} - 12 \div (1 + 1)$

Combine the numerators over the common denominator.

$\frac{18 (1 + 1) - 12 (1 + 1) + 2 \cdot 3^{2} (1 + 1) - 12}{1 + 1}$

Simplify each term.

Add $1$ and $1$ .

$\frac{18 \cdot 2 - 12 (1 + 1) + 2 \cdot 3^{2} (1 + 1) - 12}{1 + 1}$

Multiply $18$ by $2$ .

$\frac{36 - 12 (1 + 1) + 2 \cdot 3^{2} (1 + 1) - 12}{1 + 1}$

Add $1$ and $1$ .

$\frac{36 - 12 \cdot 2 + 2 \cdot 3^{2} (1 + 1) - 12}{1 + 1}$

Multiply $- 12$ by $2$ .

$\frac{36 - 24 + 2 \cdot 3^{2} (1 + 1) - 12}{1 + 1}$

Raise $3$ to the power of $2$ .

$\frac{36 - 24 + 2 \cdot 9 (1 + 1) - 12}{1 + 1}$

Multiply $2$ by $9$ .

$\frac{36 - 24 + 18 (1 + 1) - 12}{1 + 1}$

Add $1$ and $1$ .

$\frac{36 - 24 + 18 \cdot 2 - 12}{1 + 1}$

Multiply $18$ by $2$ .

$\frac{36 - 24 + 36 - 12}{1 + 1}$

Simplify the expression.

Subtract $24$ from $36$ .

$\frac{12 + 36 - 12}{1 + 1}$

Add $12$ and $36$ .

$\frac{48 - 12}{1 + 1}$

Subtract $12$ from $48$ .

$\frac{36}{1 + 1}$

Add $1$ and $1$ .

$\frac{36}{2}$

Divide $36$ by $2$ .

$18$

Evaluate 18-12+2*3^2-12÷(1+1)

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