Evaluate (19-4^2)/(3^1)

$\frac{19 - 4^{2}}{3^{1}}$

Simplify the numerator.

Raise $4$ to the power of $2$ .

$\frac{19 - 1 \cdot 16}{3^{1}}$

Multiply $- 1$ by $16$ .

$\frac{19 - 16}{3^{1}}$

Subtract $16$ from $19$ .

$\frac{3}{3^{1}}$

$\frac{3}{3^{1}}$

Evaluate the exponent.

$\frac{3}{3}$

Divide $3$ by $3$ .

$1$

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