Evaluate ((2^-1)^4)/(2^2)

$\frac{{(2^{- 1})}^{4}}{2^{2}}$

Simplify the numerator.

Multiply the exponents in ${(2^{- 1})}^{4}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2^{- 1 \cdot 4}}{2^{2}}$

Multiply $- 1$ by $4$ .

$\frac{2^{- 4}}{2^{2}}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{\frac{1}{2^{4}}}{2^{2}}$

Raise $2$ to the power of $4$ .

$\frac{\frac{1}{16}}{2^{2}}$

Raise $2$ to the power of $2$ .

$\frac{\frac{1}{16}}{4}$

Multiply the numerator by the reciprocal of the denominator.

$\frac{1}{16} \cdot \frac{1}{4}$

Multiply $\frac{1}{16} \cdot \frac{1}{4}$ .

Multiply $\frac{1}{16}$ by $\frac{1}{4}$ .

$\frac{1}{16 \cdot 4}$

Multiply $16$ by $4$ .

$\frac{1}{64}$

The result can be shown in multiple forms.

Exact Form:

$\frac{1}{64}$

Decimal Form:

$0.015625$