Evaluate (2^3a^-3)/(8^-1b^-5c^0)

$\frac{2^{3} a^{- 3}}{8^{- 1} b^{- 5} c^{0}}$

Simplify the expression.

Move $a^{- 3}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{2^{3}}{8^{- 1} b^{- 5} c^{0} a^{3}}$

Move $8^{- 1}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{2^{3} \cdot 8}{b^{- 5} a^{3}}$

Move $b^{- 5}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{2^{3} \cdot 8 b^{5}}{a^{3}}$

Simplify the numerator.

Rewrite $8$ as $2^{3}$ .

$\frac{2^{3} \cdot 2^{3} b^{5}}{a^{3}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2^{3 + 3} b^{5}}{a^{3}}$

Add $3$ and $3$ .

$\frac{2^{6} b^{5}}{a^{3}}$

Raise $2$ to the power of $6$ .

$\frac{64 b^{5}}{a^{3}}$