Evaluate (-2^-4)/(3^-3)

$\frac{- 2^{- 4}}{3^{- 3}}$

Step 1

Move $2^{- 4}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{- 1}{3^{- 3} \cdot 2^{4}}$

Step 2

Move $3^{- 3}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{- 3^{3}}{2^{4}}$

Step 3

Raise $3$ to the power of $3$ .

$\frac{- 1 \cdot 27}{2^{4}}$

Step 4

Raise $2$ to the power of $4$ .

$\frac{- 1 \cdot 27}{16}$

Step 5

Multiply $- 1$ by $27$ .

$\frac{- 27}{16}$

Step 6

Move the negative in front of the fraction.

$- \frac{27}{16}$

Step 7

The result can be shown in multiple forms.

Exact Form:

$- \frac{27}{16}$

Decimal Form:

$- 1.6875$

Mixed Number Form:

$- 1 \frac{11}{16}$