Evaluate |2-5|-(6÷2+1)^2

$| 2 - 5 | - {(6 \div 2 + 1)}^{2}$

Simplify each term.

Subtract $5$ from $2$ .

$| - 3 | - {(6 \div 2 + 1)}^{2}$

The absolute value is the distance between a number and zero. The distance between $- 3$ and $0$ is $3$ .

$3 - {(6 \div 2 + 1)}^{2}$

Divide $6$ by $2$ .

$3 - {(3 + 1)}^{2}$

Add $3$ and $1$ .

$3 - 4^{2}$

Raise $4$ to the power of $2$ .

$3 - 1 \cdot 16$

Multiply $- 1$ by $16$ .

$3 - 16$

Subtract $16$ from $3$ .

$- 13$