Evaluate 2(8x-4)-2x<=14x+12

$2 (8 x - 4) - 2 x \leq 14 x + 12$

Simplify $2 (8 x - 4) - 2 x$ .

Simplify each term.

Apply the distributive property.

$2 (8 x) + 2 \cdot - 4 - 2 x \leq 14 x + 12$

Multiply $8$ by $2$ .

$16 x + 2 \cdot - 4 - 2 x \leq 14 x + 12$

Multiply $2$ by $- 4$ .

$16 x - 8 - 2 x \leq 14 x + 12$

Subtract $2 x$ from $16 x$ .

$14 x - 8 \leq 14 x + 12$

Move all terms containing $x$ to the left side of the inequality.

Subtract $14 x$ from both sides of the inequality.

$14 x - 8 - 14 x \leq 12$

Combine the opposite terms in $14 x - 8 - 14 x$ .

Subtract $14 x$ from $14 x$ .

$0 - 8 \leq 12$

Subtract $8$ from $0$ .

$- 8 \leq 12$

Since $- 8 \leq 12$ , the inequality will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$