Evaluate 2^( log base 2 of 6-3)

$2^{\log_{2} (6) - 3}$

The change of base rule can be used if $a$ and $b$ are greater than $0$ and not equal to $1$ , and $x$ is greater than $0$ .

$2^{\log_{a} (x) = \frac{\log_{b} (x)}{\log_{b} (a)} - 3}$

Substitute in values for the variables in the change of base formula, using $b = 10$ .

$2^{\frac{\log (6)}{\log (2)} - 3}$

The result can be shown in multiple forms.

Exact Form:

$2^{\frac{\log (6)}{\log (2)} - 3}$

Decimal Form:

$0.75$