Evaluate 2(n+2)=4n+1-2n

$2 (n + 2) = 4 n + 1 - 2 n$

Since $n$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$4 n + 1 - 2 n = 2 (n + 2)$

Subtract $2 n$ from $4 n$ .

$2 n + 1 = 2 (n + 2)$

Simplify $2 (n + 2)$ .

Apply the distributive property.

$2 n + 1 = 2 n + 2 \cdot 2$

Multiply $2$ by $2$ .

$2 n + 1 = 2 n + 4$

Move all terms containing $n$ to the left side of the equation.

Subtract $2 n$ from both sides of the equation.

$2 n + 1 - 2 n = 4$

Combine the opposite terms in $2 n + 1 - 2 n$ .

Subtract $2 n$ from $2 n$ .

$0 + 1 = 4$

Add $0$ and $1$ .

$1 = 4$

Since $1 \neq 4$ , there are no solutions.

No solution