Evaluate (2 square root of 7)^2

${(2 \sqrt{7})}^{2}$

Step 1

Simplify the expression.

Apply the product rule to $2 \sqrt{7}$ .

$2^{2} {\sqrt{7}}^{2}$

Raise $2$ to the power of $2$ .

$4 {\sqrt{7}}^{2}$

Step 2

Rewrite ${\sqrt{7}}^{2}$ as $7$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{7}$ as $7^{\frac{1}{2}}$ .

$4 {(7^{\frac{1}{2}})}^{2}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 \cdot 7^{\frac{1}{2} \cdot 2}$

Combine $\frac{1}{2}$ and $2$ .

$4 \cdot 7^{\frac{2}{2}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$4 \cdot 7^{\frac{2}{2}}$

Rewrite the expression.

$4 \cdot 7^{1}$

Evaluate the exponent.

$4 \cdot 7$

Step 3

Multiply $4$ by $7$ .

$28$