Evaluate 2 square root of 9-4+ square root of 3

$2 \sqrt{9} - 4 + \sqrt{3}$

Step 1

Simplify each term.

Rewrite $9$ as $3^{2}$ .

$2 \sqrt{3^{2}} - 4 + \sqrt{3}$

Pull terms out from under the radical, assuming positive real numbers.

$2 \cdot 3 - 4 + \sqrt{3}$

Multiply $2$ by $3$ .

$6 - 4 + \sqrt{3}$

Step 2

Subtract $4$ from $6$ .

$2 + \sqrt{3}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$2 + \sqrt{3}$

Decimal Form:

$3.73205080 \dots$