Evaluate 2(x+5)=3x+1

$2 (x + 5) = 3 x + 1$

Simplify $2 (x + 5)$ .

Rewrite.

$0 + 0 + 2 (x + 5) = 3 x + 1$

Simplify by adding zeros.

$2 (x + 5) = 3 x + 1$

Apply the distributive property.

$2 x + 2 \cdot 5 = 3 x + 1$

Multiply $2$ by $5$ .

$2 x + 10 = 3 x + 1$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$2 x + 10 - 3 x = 1$

Subtract $3 x$ from $2 x$ .

$- x + 10 = 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$- x = 1 - 10$

Subtract $10$ from $1$ .

$- x = - 9$

Divide each term in $- x = - 9$ by $- 1$ and simplify.

Divide each term in $- x = - 9$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 9}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 9}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 9}{- 1}$

Simplify the right side.

Divide $- 9$ by $- 1$ .

$x = 9$