Evaluate 24+6÷3-2(4+1)

$24 + 6 \div 3 - 2 (4 + 1)$

Step 1

Find the common denominator.

Write $24$ as a fraction with denominator $1$ .

$\frac{24}{1} + 6 \div 3 - 2 (4 + 1)$

Multiply $\frac{24}{1}$ by $\frac{3}{3}$ .

$\frac{24}{1} \cdot \frac{3}{3} + 6 \div 3 - 2 (4 + 1)$

Multiply $\frac{24}{1}$ by $\frac{3}{3}$ .

$\frac{24 \cdot 3}{3} + 6 \div 3 - 2 (4 + 1)$

Write $- 2 (4 + 1)$ as a fraction with denominator $1$ .

$\frac{24 \cdot 3}{3} + 6 \div 3 + \frac{- 2 (4 + 1)}{1}$

Multiply $\frac{- 2 (4 + 1)}{1}$ by $\frac{3}{3}$ .

$\frac{24 \cdot 3}{3} + 6 \div 3 + \frac{- 2 (4 + 1)}{1} \cdot \frac{3}{3}$

Multiply $\frac{- 2 (4 + 1)}{1}$ by $\frac{3}{3}$ .

$\frac{24 \cdot 3}{3} + 6 \div 3 + \frac{- 2 (4 + 1) \cdot 3}{3}$

Step 2

Combine the numerators over the common denominator.

$\frac{24 \cdot 3 + 6 - 2 (4 + 1) \cdot 3}{3}$

Step 3

Simplify each term.

Multiply $24$ by $3$ .

$\frac{72 + 6 - 2 (4 + 1) \cdot 3}{3}$

Add $4$ and $1$ .

$\frac{72 + 6 - 2 \cdot 5 \cdot 3}{3}$

Multiply $- 2 \cdot 5 \cdot 3$ .

Multiply $- 2$ by $5$ .

$\frac{72 + 6 - 10 \cdot 3}{3}$

Multiply $- 10$ by $3$ .

$\frac{72 + 6 - 30}{3}$

Step 4

Simplify the expression.

Add $72$ and $6$ .

$\frac{78 - 30}{3}$

Subtract $30$ from $78$ .

$\frac{48}{3}$

Divide $48$ by $3$ .

$16$