Evaluate (2ab^-1)/(3e^-3d)

$\frac{2 a b^{- 1}}{3 e^{- 3} d}$

Step 1

Move $b^{- 1}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{2 a}{3 e^{- 3} d b}$

Step 2

Move $e^{- 3}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{2 a e^{3}}{3 d b}$