Evaluate 3(10-(4-9)+15÷3-2(7+10))-6

$3 (10 - (4 - 9) + 15 \div 3 - 2 (7 + 10)) - 6$

Step 1

Simplify each term.

Find the common denominator.

Write $10$ as a fraction with denominator $1$ .

$3 (\frac{10}{1} - (4 - 9) + 15 \div 3 - 2 (7 + 10)) - 6$

Multiply $\frac{10}{1}$ by $\frac{3}{3}$ .

$3 (\frac{10}{1} \cdot \frac{3}{3} - (4 - 9) + 15 \div 3 - 2 (7 + 10)) - 6$

Multiply $\frac{10}{1}$ by $\frac{3}{3}$ .

$3 (\frac{10 \cdot 3}{3} - (4 - 9) + 15 \div 3 - 2 (7 + 10)) - 6$

Write $- (4 - 9)$ as a fraction with denominator $1$ .

$3 (\frac{10 \cdot 3}{3} + \frac{- (4 - 9)}{1} + 15 \div 3 - 2 (7 + 10)) - 6$

Multiply $\frac{- (4 - 9)}{1}$ by $\frac{3}{3}$ .

$3 (\frac{10 \cdot 3}{3} + \frac{- (4 - 9)}{1} \cdot \frac{3}{3} + 15 \div 3 - 2 (7 + 10)) - 6$

Multiply $\frac{- (4 - 9)}{1}$ by $\frac{3}{3}$ .

$3 (\frac{10 \cdot 3}{3} + \frac{- (4 - 9) \cdot 3}{3} + 15 \div 3 - 2 (7 + 10)) - 6$

Write $- 2 (7 + 10)$ as a fraction with denominator $1$ .

$3 (\frac{10 \cdot 3}{3} + \frac{- (4 - 9) \cdot 3}{3} + 15 \div 3 + \frac{- 2 (7 + 10)}{1}) - 6$

Multiply $\frac{- 2 (7 + 10)}{1}$ by $\frac{3}{3}$ .

$3 (\frac{10 \cdot 3}{3} + \frac{- (4 - 9) \cdot 3}{3} + 15 \div 3 + \frac{- 2 (7 + 10)}{1} \cdot \frac{3}{3}) - 6$

Multiply $\frac{- 2 (7 + 10)}{1}$ by $\frac{3}{3}$ .

$3 (\frac{10 \cdot 3}{3} + \frac{- (4 - 9) \cdot 3}{3} + 15 \div 3 + \frac{- 2 (7 + 10) \cdot 3}{3}) - 6$

Combine the numerators over the common denominator.

$3 \frac{10 \cdot 3 - (4 - 9) \cdot 3 + 15 - 2 (7 + 10) \cdot 3}{3} - 6$

Simplify each term.

Multiply $10$ by $3$ .

$3 \frac{30 - (4 - 9) \cdot 3 + 15 - 2 (7 + 10) \cdot 3}{3} - 6$

Subtract $9$ from $4$ .

$3 \frac{30 - - 5 \cdot 3 + 15 - 2 (7 + 10) \cdot 3}{3} - 6$

Multiply $- - 5 \cdot 3$ .

Multiply $- 1$ by $- 5$ .

$3 \frac{30 + 5 \cdot 3 + 15 - 2 (7 + 10) \cdot 3}{3} - 6$

Multiply $5$ by $3$ .

$3 \frac{30 + 15 + 15 - 2 (7 + 10) \cdot 3}{3} - 6$

Add $7$ and $10$ .

$3 \frac{30 + 15 + 15 - 2 \cdot 17 \cdot 3}{3} - 6$

Multiply $- 2 \cdot 17 \cdot 3$ .

Multiply $- 2$ by $17$ .

$3 \frac{30 + 15 + 15 - 34 \cdot 3}{3} - 6$

Multiply $- 34$ by $3$ .

$3 \frac{30 + 15 + 15 - 102}{3} - 6$

Add $30$ and $15$ .

$3 \frac{45 + 15 - 102}{3} - 6$

Add $45$ and $15$ .

$3 \frac{60 - 102}{3} - 6$

Subtract $102$ from $60$ .

$3 (\frac{- 42}{3}) - 6$

Cancel the common factor of $3$ .

Cancel the common factor.

$3 (\frac{- 42}{3}) - 6$

Rewrite the expression.

$- 42 - 6$

Step 2

Subtract $6$ from $- 42$ .

$- 48$

Evaluate 3(10-(4-9)+15÷3-2(7+10))-6

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