Evaluate 3(16)^(1/2)-9

$3 {(16)}^{\frac{1}{2}} - 9$

Step 1

Simplify each term.

Rewrite $16$ as $4^{2}$ .

$3 {(4^{2})}^{\frac{1}{2}} - 9$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$3 \cdot 4^{2 (\frac{1}{2})} - 9$

Cancel the common factor of $2$ .

Cancel the common factor.

$3 \cdot 4^{2 (\frac{1}{2})} - 9$

Rewrite the expression.

$3 \cdot 4^{1} - 9$

Evaluate the exponent.

$3 \cdot 4 - 9$

Multiply $3$ by $4$ .

$12 - 9$

Step 2

Subtract $9$ from $12$ .

$3$