Evaluate (-3^-2)/(2^-3)

$\frac{- 3^{- 2}}{2^{- 3}}$

Move $3^{- 2}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{- 1}{2^{- 3} \cdot 3^{2}}$

Move $2^{- 3}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{- 2^{3}}{3^{2}}$

Raise $2$ to the power of $3$ .

$\frac{- 1 \cdot 8}{3^{2}}$

Raise $3$ to the power of $2$ .

$\frac{- 1 \cdot 8}{9}$

Multiply $- 1$ by $8$ .

$\frac{- 8}{9}$

Move the negative in front of the fraction.

$- \frac{8}{9}$

The result can be shown in multiple forms.

Exact Form:

$- \frac{8}{9}$

Decimal Form:

$- 0.\overline{8}$