Evaluate 3(-2/3+4/9)

$3 (- \frac{2}{3} + \frac{4}{9})$

To write $- \frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$3 (- \frac{2}{3} \cdot \frac{3}{3} + \frac{4}{9})$

Write each expression with a common denominator of $9$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{2}{3}$ by $\frac{3}{3}$ .

$3 (- \frac{2 \cdot 3}{3 \cdot 3} + \frac{4}{9})$

Multiply $3$ by $3$ .

$3 (- \frac{2 \cdot 3}{9} + \frac{4}{9})$

Combine the numerators over the common denominator.

$3 \frac{- 2 \cdot 3 + 4}{9}$

Simplify the numerator.

Multiply $- 2$ by $3$ .

$3 \frac{- 6 + 4}{9}$

Add $- 6$ and $4$ .

$3 (\frac{- 2}{9})$

Cancel the common factor of $3$ .

Factor $3$ out of $9$ .

$3 \frac{- 2}{3 (3)}$

Cancel the common factor.

$3 \frac{- 2}{3 \cdot 3}$

Rewrite the expression.

$\frac{- 2}{3}$

Move the negative in front of the fraction.

$- \frac{2}{3}$

The result can be shown in multiple forms.

Exact Form:

$- \frac{2}{3}$

Decimal Form:

$- 0.\overline{6}$