Evaluate 3(2x-5)=6x-15

$3 (2 x - 5) = 6 x - 15$

Simplify $3 (2 x - 5)$ .

Rewrite.

$0 + 0 + 3 (2 x - 5) = 6 x - 15$

Simplify by adding zeros.

$3 (2 x - 5) = 6 x - 15$

Apply the distributive property.

$3 (2 x) + 3 \cdot - 5 = 6 x - 15$

Multiply.

Multiply $2$ by $3$ .

$6 x + 3 \cdot - 5 = 6 x - 15$

Multiply $3$ by $- 5$ .

$6 x - 15 = 6 x - 15$

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$6 x - 15 - 6 x = - 15$

Combine the opposite terms in $6 x - 15 - 6 x$ .

Subtract $6 x$ from $6 x$ .

$0 - 15 = - 15$

Subtract $15$ from $0$ .

$- 15 = - 15$

Since $- 15 = - 15$ , the equation will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$