Evaluate (3^-2x^-5)/(y^0)

$\frac{3^{- 2} x^{- 5}}{y^{0}}$

Step 1

Simplify the expression.

Move $3^{- 2}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{x^{- 5}}{y^{0} \cdot 3^{2}}$

Move $x^{- 5}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{y^{0} \cdot 3^{2} x^{5}}$

Step 2

Simplify the denominator.

Anything raised to $0$ is $1$ .

$\frac{1}{1 \cdot 3^{2} x^{5}}$

Raise $3$ to the power of $2$ .

$\frac{1}{1 \cdot 9 x^{5}}$

Multiply $9$ by $1$ .

$\frac{1}{9 x^{5}}$