Evaluate (3-4^2)^2+8

${(3 - 4^{2})}^{2} + 8$

Step 1

Simplify each term.

Simplify each term.

Raise $4$ to the power of $2$ .

${(3 - 1 \cdot 16)}^{2} + 8$

Multiply $- 1$ by $16$ .

${(3 - 16)}^{2} + 8$

${(3 - 16)}^{2} + 8$

Subtract $16$ from $3$ .

${(- 13)}^{2} + 8$

Raise $- 13$ to the power of $2$ .

$169 + 8$

$169 + 8$

Step 2

Add $169$ and $8$ .

$177$

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