Evaluate 3*(9-(4+2)÷2)

$3 \times (9 - (4 + 2) \div 2)$

Step 1

Simplify each term.

Rewrite the division as a fraction.

$3 \cdot (9 - \frac{4 + 2}{2})$

Cancel the common factor of $4 + 2$ and $2$ .

Factor $2$ out of $4$ .

$3 \cdot (9 - \frac{2 \cdot 2 + 2}{2})$

Factor $2$ out of $2$ .

$3 \cdot (9 - \frac{2 \cdot 2 + 2 \cdot 1}{2})$

Factor $2$ out of $2 \cdot 2 + 2 \cdot 1$ .

$3 \cdot (9 - \frac{2 \cdot (2 + 1)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$3 \cdot (9 - \frac{2 \cdot (2 + 1)}{2 (1)})$

Cancel the common factor.

$3 \cdot (9 - \frac{2 \cdot (2 + 1)}{2 \cdot 1})$

Rewrite the expression.

$3 \cdot (9 - \frac{2 + 1}{1})$

Divide $2 + 1$ by $1$ .

$3 \cdot (9 - (2 + 1))$

$3 \cdot (9 - (2 + 1))$

$3 \cdot (9 - (2 + 1))$

Add $2$ and $1$ .

$3 \cdot (9 - 1 \cdot 3)$

Multiply $- 1$ by $3$ .

$3 \cdot (9 - 3)$

$3 \cdot (9 - 3)$

Step 2

Simplify the expression.

Subtract $3$ from $9$ .

$3 \cdot 6$

Multiply $3$ by $6$ .

$18$

$18$

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