Evaluate 3(x-4)=2(-2x+1)

$3 (x - 4) = 2 (- 2 x + 1)$

Simplify $3 (x - 4)$ .

Start simplifying.

$0 + 0 + 3 (x - 4) = 2 (- 2 x + 1)$

Simplify by adding zeros.

$3 (x - 4) = 2 (- 2 x + 1)$

Apply the distributive property.

$3 x + 3 \cdot - 4 = 2 (- 2 x + 1)$

Multiply $3$ by $- 4$ .

$3 x - 12 = 2 (- 2 x + 1)$

Simplify $2 (- 2 x + 1)$ .

Apply the distributive property.

$3 x - 12 = 2 (- 2 x) + 2 \cdot 1$

Multiply.

Multiply $- 2$ by $2$ .

$3 x - 12 = - 4 x + 2 \cdot 1$

Multiply $2$ by $1$ .

$3 x - 12 = - 4 x + 2$

Move all terms containing $x$ to the left side of the equation.

Add $4 x$ to both sides of the equation.

$3 x - 12 + 4 x = 2$

Add $3 x$ and $4 x$ .

$7 x - 12 = 2$

Move all terms not containing $x$ to the right side of the equation.

Add $12$ to both sides of the equation.

$7 x = 2 + 12$

Add $2$ and $12$ .

$7 x = 14$

Divide each term in $7 x = 14$ by $7$ and simplify.

Divide each term in $7 x = 14$ by $7$ .

$\frac{7 x}{7} = \frac{14}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{14}{7}$

Divide $x$ by $1$ .

$x = \frac{14}{7}$

Simplify the right side.

Divide $14$ by $7$ .

$x = 2$