Evaluate 3(x-6)=100+x

$3 (x - 6) = 100 + x$

Step 1

Simplify $3 (x - 6)$ .

Rewrite.

$0 + 0 + 3 (x - 6) = 100 + x$

Simplify by adding zeros.

$3 (x - 6) = 100 + x$

Apply the distributive property.

$3 x + 3 \cdot - 6 = 100 + x$

Multiply $3$ by $- 6$ .

$3 x - 18 = 100 + x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$3 x - 18 - x = 100$

Subtract $x$ from $3 x$ .

$2 x - 18 = 100$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $18$ to both sides of the equation.

$2 x = 100 + 18$

Add $100$ and $18$ .

$2 x = 118$

Step 4

Divide each term in $2 x = 118$ by $2$ and simplify.

Divide each term in $2 x = 118$ by $2$ .

$\frac{2 x}{2} = \frac{118}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{118}{2}$

Divide $x$ by $1$ .

$x = \frac{118}{2}$

Simplify the right side.

Divide $118$ by $2$ .

$x = 59$